Two charges, each of `5 mu C` but opposite in sign, are placed 4 cm apart. Calculate the electric field intensity of a point that is a distance 4 cm from the mid point on the axial line of the dipole.

Explanation

To solve the problem, we need to calculate the electric field intensity at a point that is 4 cm from the midpoint of a dipole formed by two charges of equal magnitude but opposite sign. Here’s a step-by-step solution:

### Step 1: Understand the Configuration
We have two charges:
- Charge \( Q_1 = +5 \, \mu C = 5 \times 10^{-6} \, C \)
- Charge \( Q_2 = -5 \, \mu C = -5 \times 10^{-6} \, C \)

The distance between the two charges is \( d = 4 \, cm = 0.04 \, m \). The point where we need to calculate the electric field intensity is located 4 cm from the midpoint of the dipole along the axial line.
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