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The two conducting spherical shells are ...

The two conducting spherical shells are joined by a conducting wire and cut after some time when charge stops flowing. Find out the charge on each sphere after that.

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After cutting the wire, the potential of both the shells is equal
Thus, potential of inner shell, `V_("in")=(Kx)/R+ (K(-2Q-x))/(@R)=(k(x-2q))/(2R)`
and potential of outer shell, `V_("out")=(Kx)/(2R)+(K(-2Q-x))/(2R)=(-KQ)/R`
As, `V_("out")=V_("in")`
`implies (-KQ)/R=(K(x-2Q))/(2R)implies" "-2Q=x-2Q" "implies" "x=0`
So, charge on inner spherical shell = 0 and outer spherical shell `= -2Q`
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