Home
Class 12
PHYSICS
A particle of charges Q and mass m m tra...

A particle of charges Q and mass m `m` travels through a potential difference V from rest. The final momentum of the particle is

A

`(mV)/Q`

B

`2Q sqrt(mV)`

C

`sqrt(2mQV)`

D

`sqrt((2QV)/m)`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • ELECTROSTATICS

    RESONANCE ENGLISH|Exercise Part - II Section (D)|2 Videos

  • ELECTROSTATICS

    RESONANCE ENGLISH|Exercise Part - II Section (E)|2 Videos

  • ELECTROSTATICS

    RESONANCE ENGLISH|Exercise Part - II Section (B)|9 Videos

  • ELECTROMAGNETIC INDUCTION

    RESONANCE ENGLISH|Exercise A.l.P|19 Videos

  • EXPERIMENTAL PHYSICS

    RESONANCE ENGLISH|Exercise PART -II|10 Videos

Similar Questions

Explore conceptually related problems

A particle of charges Q and mass m travels through a potential difference V from rest. The final momentum of the particle is

An electron of mass m and charge e is accelerated from rest through a potential difference V in vacuum. The final speed of the electron will be

An electron of mass m and charge e is accelerated from rest through a potential difference V in vacuum. The final speed of the electron will be

A charged particle of mass m and charge q is accelerated through a potential differences of V volts. It enters of uniform magnetic field B which is directed perpendicular to the direction of motion of the particle. The particle will move on a circular path of radius

An alpha particle ( charge = +2e) is accelerated from rest through a potential difference of 500 volts . Its final kinetic energy as

A charged particle of mass m and charge q is accelerated through a potential difference of V volts. It enters a region of uniform magnetic field which is directed perpendicular to the direction of motion of the particle. Find the radius of circular path moved by the particle in magnetic field.

An alpha-"particle" is accelerated through a potential difference of V volts from rest. The de-Broglie's wavelengths associated with it is.

An alpha-"particle" is accelerated through a potential difference of V volts from rest. The de-Broglie's wavelengths associated with it is.

An alpha particle is accelerated from rest through a potential difference of 100 volt. Its final kinetic energy is

The mass of an electron is m, its charge is e and it is accelerated from rest through a potential difference, V. The velocity of electron can be calculated by formula: