The potential difference between two large parallel plates is varied as v = at, a is a positive constant and t is time. An electron starts from rest at t=0 from the plate which is at lower potential. If the distance between the plates is L, mass of electron m and charge on electron -e then find the velocity of the electron when it reaches the other plate.

In an electron gun, the electrons are accelerated by the potential V . If the e is the charge and m is the mass of the electron, then the maximum velocity of these electrons will be

The distnace between the plates of a parallel plate capacitor is 3 mm the potential difference applied is 3xx10^(5) V. If an electron travels from one plate to another the change in its potential energy is

An electron having charge e and mass m starts from the lower plate of two metallic plates separated by a distance d . If the potential difference between the plates is V , the time taken by the electron to reach the upper plate is given by .

The electric potential difference between two parallel plates is 2000 V . If the plates are separated by 2 mm, then what is the magnitude of electrostatic force on a charge of 4 xx 10^(-6)C located midway between the plates ?

The plates of small size of a parallel plate capacitor are charged as shown. The force on the charged particle of 'q' at a distance 'l' from the capacitor is : (Assume that the distance between the plates is d ltlt l )

The plates of small size of a parallel plate capacitor are charged as shown. The force on the charged particle of 'q' at a distance 'l' from the capacitor is : (Assume that the distance between the plates is d ltlt l )

The force between the plates of a parallel plate capacitor of capacitance C and distance of separation of the plates d with a potential difference V between the plates, is.

The potential enery of a charged parallel plate capacitor is U_(0) . If a slab of dielectric constant K is inserted between the plates, then the new potential energy will be

The potential enery of a charged parallel plate capacitor is U_(0) . If a slab of dielectric constant K is inserted between the plates, then the new potential energy will be

A parallel plate capacitor of plate area A and plate separation d is charged to potential difference V and then the battery is disconnected. A slab of dielectric constant K is then inserted between the plates of the capacitor so as to fill the space between the plates. If Q, E and W denote respectively, the magnitude of charge on each plate, the electric field between the plates (after the slab is inserted), and work done on the system, in question, in the process of inserting the slab, then