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Four similar particles of mass m are orb...

Four similar particles of mass m are orbiting in a circle of radius r in the same direction and same speed because of their mutual gravitational attractive force as shown in the figure . Speed of a particle is given by

A

`[(Gm)/(r)((1+2sqrt2)/(4))]^(1/(2))`

B

`root(3)((GM)/(r))`

C

`sqrt((Gm)/(r)(1+2sqrt2))`

D

zero

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • Two particles of equal mass go around a circle of radius R under the action of their mutual gravitational attraction. The speed v of each particle is

    A
    `(1)/(2R ) sqrt(((1)/(Gm)))`
    B
    ` sqrt(((Gm)/(2R)))`
    C
    `(1)/(2)sqrt(((Gm)/(R )))`
    D
    `sqrt(((4Gm)/(R )))`

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