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The height at which the acceleration due...

The height at which the acceleration due to gravity becomes `(g)/(9)` (where g = the accleeration due to gravity on the surface of the earth) in terms of R, the radius of the earth is

A

`(R)/(sqrt2)`

B

`(R)/(2)`

C

`sqrt2R`

D

`2R`

Text Solution

Verified by Experts

The correct Answer is:
D
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