Home
Class 12
PHYSICS
The mass of a spaceship is 1000 kg. It i...

The mass of a spaceship is 1000 kg. It is to be launched from the earth's surface out into free space. The value of 'g' and 'R' (radius of earth) are `10 m//s^(2)` and 6400 km respectively. The required energy for this work will be :

A

`6.4 xx 10^(11)` Joules

B

`6.4 xx 10^(8)` Joules

C

`6.4 xx 10^(9)` Joules

D

`6.4 xx 10^(10)` Joules

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    RESONANCE ENGLISH|Exercise HIGH LEVEL PROBLEMS|16 Videos
  • GRAVITATION

    RESONANCE ENGLISH|Exercise EXERCISE-3 PART-1|15 Videos
  • GEOMATRICAL OPTICS

    RESONANCE ENGLISH|Exercise Advance level Problems|35 Videos
  • NUCLEAR PHYSICS

    RESONANCE ENGLISH|Exercise Advanced level solutions|16 Videos

Similar Questions

Explore conceptually related problems

The mass of a spaceship is 1000kg. It is to be launched from the earth's surface out into free space. The value of g and R (radius of earth) are 10m/s^2 and 6400 km respectively. The required energy for this work will be:

If a body of mass m is raised to height 2 R from the earth s surface, then the change in potential energy of the body is (R is the radius of earth)

What is the energy required to launch a m kg satellite from earth's surface in a circular orbit at an altitude of 7R ? (R = radius of the earth)

At what height above the surface of earth the value of "g" decreases by 2 % [ radius of the earth is 6400 km ]

At what height from the surface of earth the gravitation potential and the value of g are - 5.4 xx 10^(7) J kg^(-2) and 6.0 ms^(-2) respectively ? Take the radius of earth as 6400 km :

At what height from the surface of earth the gravitation potential and the value of g are - 5.4 xx 10^(7) J kg^(-2) and 6.0 ms^(-2) respectively ? Take the radius of earth as 6400 km :

A what height above the earth's surface the value of g becomes 25% of its value on the earth if radius of the earth is 6400km.

If 'g' on the surface of the earth is 9.8ms^(-2) , find its value at a depth of 3200 km (radius of the earth = 6400 km)

If body of mass m has to be taken from the surface to the earth to a height h=4R , then the amount of energy required is (R = radius of the earth)

At what height from the surface of earth will the value of g be reduced by 36% from the value on the surface? Take radius of earth R = 6400 km .