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If f(x)=log(10)x and g(x)=e^(ln x) and h...

If `f(x)=log_(10)x and g(x)=e^(ln x) and h(x)=f [g(x)]`, then find the value of h(10).

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To solve the problem step by step, we will follow the definitions of the functions given and calculate \( h(10) \). ### Step 1: Define the functions We have the following functions defined: - \( f(x) = \log_{10} x \) - \( g(x) = e^{\ln x} \) - \( h(x) = f[g(x)] \) ### Step 2: Simplify \( g(x) \) We know from properties of logarithms and exponentials that: \[ g(x) = e^{\ln x} = x \] This is because the exponential function \( e \) and the natural logarithm \( \ln \) are inverse functions. ### Step 3: Substitute \( g(x) \) into \( h(x) \) Now we substitute \( g(x) \) into \( h(x) \): \[ h(x) = f[g(x)] = f[x] \] This means that \( h(x) \) is simply \( f(x) \). ### Step 4: Calculate \( h(10) \) Now we need to find \( h(10) \): \[ h(10) = f(10) \] Substituting into the function \( f \): \[ f(10) = \log_{10}(10) \] ### Step 5: Evaluate \( \log_{10}(10) \) We know that: \[ \log_{10}(10) = 1 \] ### Final Answer Thus, the value of \( h(10) \) is: \[ h(10) = 1 \]
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