Calculate mass of carbon in 0.01 mole of `K_4[Fe(CN)_6]` Report your answer after dividing by 0.08

Answer

To calculate the mass of carbon in 0.01 mole of \( K_4[Fe(CN)_6] \) and report the answer after dividing by 0.08, follow these steps:

### Step 1: Determine the number of moles of carbon in the complex
In the formula \( K_4[Fe(CN)_6] \), we can see that there are 6 cyanide ions (CN) in the complex. Each cyanide ion contains one carbon atom. Therefore, in 1 mole of \( K_4[Fe(CN)_6] \), there are 6 moles of carbon.

\[ \text{Moles of carbon in 1 mole of } K_4[Fe(CN)_6] = 6 \text{ moles} \]

### Step 2: Calculate the moles of carbon in 0.01 mole of the complex
To find the moles of carbon in 0.01 mole of \( K_4[Fe(CN)_6] \):

\[ \text{Moles of carbon in 0.01 mole} = 6 \times 0.01 = 0.06 \text{ moles} \]

### Step 3: Calculate the mass of carbon
The molar mass of carbon (C) is approximately 12 g/mol. To find the mass of 0.06 moles of carbon:

\[ \text{Mass of carbon} = \text{Moles of carbon} \times \text{Molar mass of carbon} \]

\[ \text{Mass of carbon} = 0.06 \text{ moles} \times 12 \text{ g/mol} = 0.72 \text{ g} \]

### Step 4: Divide the mass of carbon by 0.08
Now, we need to divide the mass of carbon by 0.08 as per the question:

\[ \text{Final result} = \frac{0.72 \text{ g}}{0.08} = 9 \]

### Final Answer
The final answer is 9.

---