A chemist was performing an experiment to study the effect of varying voltage and de-Broglie wavelength of the electron. In first experiment, the electron was accelerated through a potential difference of 1 kV from rest and in second experiment, it was accelerated through a potential difference of 2 kV from rest.
The wavelength of de-Broglie waves associated with electron is given by
`lambda=h/sqrt(2qVm)`
Where, V is the voltage through which one electron is accelerated
Putting the values of h, m and q, we get
`lambda=12.3 /sqrtV Å`
Answer the following question
The wavelength of electron will be :

Options

A. 14 times in first case than in second case
B. double in second case than in first case
C. 1.4 times in second case than in first case
D. double in first case than in second case