Zinc sulphide reacts with dilute `H_(2)SO_(4)` to liberate which gas.

Options

A. `O_(2)`
B. `SO_(3)`
C. `H_(2)S`
D. `SO_(2)`

Answer

To determine which gas is liberated when zinc sulphide reacts with dilute sulfuric acid, we can follow these steps:

### Step 1: Write the chemical equation for the reaction.
Zinc sulphide (ZnS) reacts with dilute sulfuric acid (H₂SO₄). The reaction can be represented as:
\[ \text{ZnS} + \text{H}_2\text{SO}_4 \rightarrow \text{ZnSO}_4 + \text{H}_2\text{S} \]

### Step 2: Identify the products of the reaction.
From the equation, we can see that the products of the reaction are zinc sulfate (ZnSO₄) and hydrogen sulfide (H₂S).

### Step 3: Determine the gas evolved.
In this reaction, hydrogen sulfide (H₂S) is the gas that is evolved.

### Conclusion:
Therefore, when zinc sulphide reacts with dilute sulfuric acid, the gas liberated is hydrogen sulfide (H₂S).

### Final Answer:
The correct option is **C. Hydrogen sulfide gas (H₂S)**.

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