Find the total number of acidic radical which produce volatile product with dil HCl :
`(i) SO_(4)^(2-) " " (ii) I^(-) " " (iii) NO_(2)^(-) " " (iv) NO_(3)^(-)`
(v)` SO_(3)^(2-) " " (vi) HCO_(3)^(-)`

Answer

To determine the total number of acidic radicals that produce volatile products with dilute HCl, we will analyze each given radical one by one.

### Step-by-Step Solution:

1. **Identify the radicals**: We have the following radicals to analyze:
- (i) \( SO_4^{2-} \)
- (ii) \( I^{-} \)
- (iii) \( NO_2^{-} \)
- (iv) \( NO_3^{-} \)
- (v) \( SO_3^{2-} \)
- (vi) \( HCO_3^{-} \)

2. **Analyze each radical**:
- **(i) \( SO_4^{2-} \)**: When treated with dilute HCl, it does not produce a volatile product.
- **(ii) \( I^{-} \)**: Iodide ions do not produce a volatile product with dilute HCl.
- **(iii) \( NO_2^{-} \)**: Nitrate ions can produce nitrogen dioxide (NO2), which is a gas and thus a volatile product.
- **(iv) \( NO_3^{-} \)**: Nitrate ions do not produce a volatile product with dilute HCl.
- **(v) \( SO_3^{2-} \)**: Sulfite ions can produce sulfur dioxide (SO2), which is a gas and thus a volatile product.
- **(vi) \( HCO_3^{-} \)**: Bicarbonate ions produce carbon dioxide (CO2) when reacted with dilute HCl, which is also a volatile product.

3. **Count the volatile products**:
- From the analysis:
- \( NO_2^{-} \) produces a volatile product.
- \( SO_3^{2-} \) produces a volatile product.
- \( HCO_3^{-} \) produces a volatile product.
- Therefore, the total number of acidic radicals that produce volatile products with dilute HCl is 3.

### Final Answer:
The total number of acidic radicals that produce volatile products with dilute HCl is **3**.