concentrated sulphuric acid on reaction with NaCl, NaBr and Nal produces HCl, bromine and iodine respectively. What order of oxidising ability of halogens with reference to sulphuric acid can be established on the basis of this reaction ?

Options

A. `H_(2)SO_(4) gt l_(2) gt Br_(2) gt Cl_(2)`
B. `Cl_(2) gt H_(2)SO_(4) gt Br_(2) gt l_(2)`
C. `H_(2)SO_(4)gt Cl_(2) gt Br_(2) gt l_(2)`
D. `Cl_(2) gt Br_(2) gt l_(2) gt H_(2)SO_(4)`

Answer

To determine the order of oxidizing ability of halogens (Cl, Br, and I) with respect to concentrated sulfuric acid (H₂SO₄), we can analyze the reactions of sodium halides (NaCl, NaBr, and NaI) with concentrated sulfuric acid.

### Step-by-Step Solution:

1. **Identify the Reactions**:
- When concentrated sulfuric acid reacts with sodium chloride (NaCl), it produces hydrochloric acid (HCl).
- When it reacts with sodium bromide (NaBr), it produces bromine (Br₂).
- When it reacts with sodium iodide (NaI), it produces iodine (I₂).

2. **Write the Reactions**:
- For NaCl:
\[ \text{NaCl} + \text{H}_2\text{SO}_4 \rightarrow \text{HCl} + \text{NaHSO}_4 \]
- For NaBr:
\[ \text{NaBr} + \text{H}_2\text{SO}_4 \rightarrow \text{Br}_2 + \text{H}_2\text{SO}_4 + \text{NaHSO}_4 \]
- For NaI:
\[ \text{NaI} + \text{H}_2\text{SO}_4 \rightarrow \text{I}_2 + \text{H}_2\text{SO}_4 + \text{NaHSO}_4 \]

3. **Analyze the Products**:
- The formation of HCl from NaCl indicates that Cl⁻ is not oxidized by H₂SO₄.
- The formation of Br₂ from NaBr indicates that Br⁻ is oxidized by H₂SO₄.
- The formation of I₂ from NaI indicates that I⁻ is also oxidized by H₂SO₄.

4. **Determine the Oxidizing Ability**:
- Chlorine (Cl) does not oxidize H₂SO₄, indicating it has a lower oxidizing ability compared to sulfuric acid.
- Bromine (Br) can oxidize H₂SO₄, indicating it has a higher oxidizing ability than Cl.
- Iodine (I) can also oxidize H₂SO₄, but it is less effective than Br.

5. **Establish the Order**:
- Based on the reactions, we can establish the following order of oxidizing ability:
\[ \text{Cl} < \text{Br} < \text{I} \]
- Therefore, the order of oxidizing ability of halogens with respect to concentrated sulfuric acid is:
\[ \text{Cl} < \text{Br} < \text{I} \]

### Final Answer:
The order of oxidizing ability of halogens with reference to concentrated sulfuric acid is:
\[ \text{Cl} < \text{Br} < \text{I} \]