If a dilute solution of aqueous `NH_(3)` is saturated with `H_(2)S` then the product formed is :

Options

A. `(NH_(4))_(2)S`
B. `NH_(4)HS`
C. `(NH_(4))_(2)S_(x)`
D. `NH_(4)OH+S`

Answer

To solve the problem, we need to analyze the reaction that occurs when a dilute solution of aqueous ammonia (NH₃) is saturated with hydrogen sulfide (H₂S).

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this scenario are aqueous ammonia (NH₃) and hydrogen sulfide (H₂S).

2. **Understand the Reaction**:
- When NH₃ is saturated with H₂S, they can react to form a compound. Ammonia can react with hydrogen sulfide to form ammonium hydrogen sulfide.

3. **Write the Chemical Equation**:
- The reaction can be represented as:
\[ NH₃ + H₂S \rightarrow NH₄HS \]
- Here, NH₄HS is ammonium hydrogen sulfide.

4. **Count the Atoms**:
- On the reactant side:
- Nitrogen (N): 1 from NH₃
- Hydrogen (H): 3 from NH₃ + 2 from H₂S = 5
- Sulfur (S): 1 from H₂S
- On the product side (NH₄HS):
- Nitrogen (N): 1 from NH₄HS
- Hydrogen (H): 4 from NH₄ + 1 from HS = 5
- Sulfur (S): 1 from NH₄HS
- The number of atoms on both sides is balanced.

5. **Evaluate the Options**:
- The options provided include:
1. NH₄HS (correct)
2. NH₄₂S (incorrect, as it has 2 nitrogen atoms)
3. NH₄₂SX (not applicable)
4. NH₄OH (incorrect, as it introduces an oxygen atom not present in the reactants)
- The only valid product that matches the balanced equation is NH₄HS.

6. **Conclusion**:
- The product formed when a dilute solution of aqueous NH₃ is saturated with H₂S is **NH₄HS**.

### Final Answer:
The product formed is **NH₄HS** (ammonium hydrogen sulfide).