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How many of the following will volatiliz...

How many of the following will volatilize on heating leaving no solid residue ?
`(i) NaNO_(3) " " (ii) NH_(4)NO_(3) " " (iii)Ca(H_(2)PO_(2)) " " (iv) NH_(4)HCO_(3)`
(v)`N_(2)H_(5)HSO_(3) " " (vi)AlCl_(3) " " (vii) [Cu(NH_(3))_(4)]SO_(4) " " (viii) FeSO_(4), 7H_(2)O`

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The correct Answer is:
To determine how many of the given compounds will volatilize on heating leaving no solid residue, we will analyze each compound one by one. 1. **NaNO₃ (Sodium Nitrate)**: - On heating, NaNO₃ decomposes to form NaNO₂ (sodium nitrite) and O₂ (oxygen gas). - **Reaction**: 2 NaNO₃ → 2 NaNO₂ (s) + O₂ (g) - **Conclusion**: Solid residue (NaNO₂) remains. 2. **NH₄NO₃ (Ammonium Nitrate)**: - On heating, NH₄NO₃ decomposes to form N₂O (nitrous oxide) and O₂ (oxygen gas). - **Reaction**: 2 NH₄NO₃ → N₂O (g) + O₂ (g) - **Conclusion**: No solid residue remains. 3. **Ca(H₂PO₂)₂ (Calcium Dihydrogen Phosphate)**: - On heating, it decomposes to form calcium hydroxide, O₂, and P₄ (phosphorus). - **Reaction**: Ca(H₂PO₂)₂ → Ca(OH)₂ (s) + O₂ (g) + P₄ (s) - **Conclusion**: Solid residue (Ca(OH)₂ and P₄) remains. 4. **NH₄HCO₃ (Ammonium Bicarbonate)**: - On heating, it decomposes to form ammonia gas and CO₂ (carbon dioxide). - **Reaction**: NH₄HCO₃ → NH₃ (g) + CO₂ (g) - **Conclusion**: No solid residue remains. 5. **N₂H₅HSO₃ (Hydrazine Sulfite)**: - On heating, it decomposes to form N₂H₄ (hydrazine), O₂, and SO₂ (sulfur dioxide). - **Reaction**: N₂H₅HSO₃ → N₂H₄ (g) + O₂ (g) + SO₂ (g) - **Conclusion**: No solid residue remains. 6. **AlCl₃ (Aluminum Chloride)**: - On heating, it sublimates to form gaseous AlCl₃. - **Conclusion**: No solid residue remains. 7. **[Cu(NH₃)₄]SO₄ (Copper(II) Ammonium Sulfate)**: - On heating, it decomposes to form solid copper sulfate, ammonia, and O₂. - **Reaction**: [Cu(NH₃)₄]SO₄ → CuSO₄ (s) + NH₃ (g) + O₂ (g) - **Conclusion**: Solid residue (CuSO₄) remains. 8. **FeSO₄·7H₂O (Iron(II) Sulfate Heptahydrate)**: - On heating, it loses water and decomposes to form FeSO₄ (solid) and O₂. - **Reaction**: FeSO₄·7H₂O → FeSO₄ (s) + O₂ (g) - **Conclusion**: Solid residue (FeSO₄) remains. Now, let's summarize the results: - Compounds that leave no solid residue upon heating: NH₄NO₃, NH₄HCO₃, N₂H₅HSO₃, AlCl₃. - Compounds that leave solid residue: NaNO₃, Ca(H₂PO₂)₂, [Cu(NH₃)₄]SO₄, FeSO₄·7H₂O. **Final Count**: 4 compounds will volatilize on heating leaving no solid residue.

To determine how many of the given compounds will volatilize on heating leaving no solid residue, we will analyze each compound one by one. 1. **NaNO₃ (Sodium Nitrate)**: - On heating, NaNO₃ decomposes to form NaNO₂ (sodium nitrite) and O₂ (oxygen gas). - **Reaction**: 2 NaNO₃ → 2 NaNO₂ (s) + O₂ (g) - **Conclusion**: Solid residue (NaNO₂) remains. 2. **NH₄NO₃ (Ammonium Nitrate)**: ...
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