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H(2)S and SO(2) can be distingnisted by...

`H_(2)S and SO_(2)` can be distingnisted by

A

Litmus paper

B

`MnO_(4)^(-) // H^(+)`

C

`(CH_(3)CO O)_(2)Pb`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
`H_(2)S,SO_(2)` both are acidic so turns blue litmus red but `SO_(2)` is a bleaching agent which turns red litmus colourless.
`MnO_(4)^(-) // H^(+)` oxidising agent, so `SO_(2)` is oxidised to `SO_(4)^(2-) & H_(2)S` is oxidized to sulphur
`2MnO_(4)^(-)+5SO_(2)+2H_(2)O to 2Mn^(+2) +5SO_(4)^(-2) +4H^(+)`
`2MnO_(4)^(-)+5H_(2)S +6H^(+) to 2Mn^(+2) + underset(("yellow"))(5S)+8H_(2)O`
`Pb^(2+) +S^(2-) to PbS^(-) ("black ppt."), SO_(2)` will not give black precipitate so can be distinguished.
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