When compound (A) is treated with conc. `H_(2)SO_(4)`, a reddish brown colour gas (B) is evolved. To this solution, a solution of (C ) is added slowly from the side of the test tube, a blue ring is obtained at the junction of two layers due to formation of (D).
Compound (D) has formula :
When compound (A) is treated with conc. `H_(2)SO_(4)`, a reddish brown colour gas (B) is evolved. To this solution, a solution of (C ) is added slowly from the side of the test tube, a blue ring is obtained at the junction of two layers due to formation of (D).
Compound (D) has formula :
Compound (D) has formula :
Text Solution
AI Generated Solution
The correct Answer is:
To solve the problem step by step, we will analyze the reactions and compounds involved.
### Step 1: Identify Compound (A)
When compound (A) is treated with concentrated sulfuric acid (H₂SO₄), it produces a reddish-brown gas (B). The reddish-brown gas is likely nitrogen dioxide (NO₂), which is commonly produced from the decomposition of nitric acid (HNO₃).
**Hint for Step 1:** Think about common reactions involving concentrated sulfuric acid and nitrogen compounds.
### Step 2: Reaction of (A) with H₂SO₄
The reaction can be represented as follows:
- When a nitrate compound (like potassium nitrate, KNO₃) is treated with concentrated H₂SO₄, it produces nitric acid (HNO₃) and bisulfate ion (HSO₄⁻).
- The nitric acid can then decompose to produce nitrogen dioxide (NO₂) and water (H₂O).
**Hint for Step 2:** Consider the decomposition of nitric acid and the products formed when it reacts with sulfuric acid.
### Step 3: Identify Compound (C)
The problem states that a solution of (C) is added slowly to the solution containing the reddish-brown gas (B). The compound (C) is likely an aromatic amine, specifically aniline (C₆H₅NH₂).
**Hint for Step 3:** Think about compounds that can react with nitric acid or its derivatives to form colored complexes.
### Step 4: Formation of Compound (D)
When aniline (C₆H₅NH₂) reacts with the nascent oxygen produced from the decomposition of nitric acid, it forms a complex that gives a blue ring at the junction of two layers. This complex is known as a "blue ring" and is identified as the compound (D), which is likely to be a diazonium salt, specifically C₆H₅N₂⁺.
**Hint for Step 4:** Consider the types of colored complexes that can form from aromatic amines and how they interact with oxidizing agents.
### Step 5: Conclusion
The compound (D) that is formed, which is responsible for the blue ring, has the formula C₆H₅N₂⁺.
**Final Answer:** The formula of compound (D) is C₆H₅N₂⁺.
To solve the problem step by step, we will analyze the reactions and compounds involved.
### Step 1: Identify Compound (A)
When compound (A) is treated with concentrated sulfuric acid (H₂SO₄), it produces a reddish-brown gas (B). The reddish-brown gas is likely nitrogen dioxide (NO₂), which is commonly produced from the decomposition of nitric acid (HNO₃).
**Hint for Step 1:** Think about common reactions involving concentrated sulfuric acid and nitrogen compounds.
### Step 2: Reaction of (A) with H₂SO₄
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