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In brown ring complex, if number of ambi...

In brown ring complex, if number of ambidentate is/are "a" and oxidation state of iron is/are "b" then a+b=?

Text Solution

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The correct Answer is:
5
`a=0 " " H_(2)O,NO^(+)` are not ambidentate ligand
`b=1 " " Fe^(+1)`
`a+b=1`
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Knowledge Check

  • Oxidation state of iron in Fe(CO)_(4) is

    A
    `+1`
    B
    `-1`
    C
    `+2`
    D
    0

  • What is the oxidation state of iron in haemoglobin ?

    A
    `Fe^(-)`
    B
    `Fe^(2+)`
    C
    `Fe^(3+)`
    D
    `Fe^(4+)`

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