Which of the following is true about the complex `[PtCl_(2)(NH_(3))(OH_(2))]`? [ Atomic number of Pt=78]
(i) It will have two geometrical isomeric forms, cis and trans.
(ii) The hybridisation state of Pt(II) is `sp^(3)`.
(iii) It is a square planar complex. (iv) It is a diamagnetic complex.
(v) It can show hydrate isomerism. (vi) It is a tetrahedral complex.

Options

A. (i),(iii),(iv)
B. (ii),(iv),(v)
C. (ii),(v),(vi)
D. (i),(v),(vi)

Explanation

To determine which statements about the complex \([PtCl_2(NH_3)(OH_2)]\) are true, we will analyze each statement step by step.

### Step 1: Analyze Geometrical Isomerism
**Statement (i): It will have two geometrical isomeric forms, cis and trans.**

- The complex has two identical ligands (Cl) and two different ligands (NH3 and OH2). This allows for the possibility of geometrical isomers.
- **Cis form:** Both Cl ligands are on the same side.
- **Trans form:** The Cl ligands are opposite each other.

**Conclusion:** This statement is **true**.

### Step 2: Determine Hybridization State
**Statement (ii): The hybridization state of Pt(II) is \(sp^3\).**

- Platinum in this complex is in the +2 oxidation state. The electronic configuration of Pt(II) is \([Xe] 4f^{14} 5d^8\).
- With four ligands (two Cl, one NH3, and one OH2), the appropriate hybridization for a square planar geometry is \(dsp^2\), not \(sp^3\).

**Conclusion:** This statement is **false**.

### Step 3: Identify Geometry of the Complex
**Statement (iii): It is a square planar complex.**

- Based on the hybridization \(dsp^2\), the geometry of the complex is indeed square planar.

**Conclusion:** This statement is **true**.

### Step 4: Assess Magnetic Properties
**Statement (iv): It is a diamagnetic complex.**

- Since the complex involves pairing of electrons due to strong field ligands (Cl, NH3, OH2), it will have no unpaired electrons.
- Thus, it is diamagnetic.

**Conclusion:** This statement is **true**.

### Step 5: Check for Hydrate Isomerism
**Statement (v): It can show hydrate isomerism.**

- Hydrate isomerism occurs when water can be either inside or outside the coordination sphere. In this case, the water molecule is already coordinated to Pt and cannot leave the coordination sphere.

**Conclusion:** This statement is **false**.

### Step 6: Determine Tetrahedral vs Square Planar
**Statement (vi): It is a tetrahedral complex.**

- As established, the geometry is square planar (due to \(dsp^2\) hybridization), not tetrahedral.

**Conclusion:** This statement is **false**.

### Final Summary of True Statements
The true statements about the complex \([PtCl_2(NH_3)(OH_2)]\) are:
- (i) It will have two geometrical isomeric forms, cis and trans.
- (iii) It is a square planar complex.
- (iv) It is a diamagnetic complex.