Co-ordination number of platinum in `[Pt(NH_(3))_(4)Cl_(2)]^(2+)` ion is :

Options

A. 4
B. 2
C. 8
D. 6

Answer

To determine the coordination number of platinum in the complex ion \([Pt(NH_3)_4Cl_2]^{2+}\), we follow these steps:

### Step 1: Identify the central metal atom
The central metal atom in this complex is platinum (Pt).

**Hint:** The coordination number is always related to the central metal atom in a coordination compound.

### Step 2: Identify the ligands
The ligands attached to platinum in this complex are:
- 4 ammonia (NH₃) molecules
- 2 chloride (Cl⁻) ions

**Hint:** Ligands are molecules or ions that donate a pair of electrons to the central metal atom.

### Step 3: Determine the nature of the ligands
- Ammonia (NH₃) is a monodentate ligand, meaning it can attach to the metal at only one point.
- Chloride (Cl⁻) is also a monodentate ligand.

**Hint:** Monodentate ligands can only form one bond with the central metal atom.

### Step 4: Count the number of bonds formed by the ligands
- The 4 NH₃ ligands contribute 4 to the coordination number (1 bond each).
- The 2 Cl⁻ ligands contribute 2 to the coordination number (1 bond each).

**Hint:** Add the contributions from each type of ligand to find the total coordination number.

### Step 5: Calculate the total coordination number
Total coordination number = (Number of NH₃ ligands) + (Number of Cl⁻ ligands)
Total coordination number = 4 (from NH₃) + 2 (from Cl⁻) = 6

**Hint:** The coordination number is the sum of the contributions from all ligands.

### Conclusion
The coordination number of platinum in the complex \([Pt(NH_3)_4Cl_2]^{2+}\) is 6.

**Final Answer:** 6