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Total number of paramagnetic complexes w...

Total number of paramagnetic complexes which are inner orbital complexes :
`(i) [Cr(NH_(3))_(6)]Cl_(3) " " (ii)[Co(NH_(3))_(6)](NO_(3))_(2)" " (iii)[Ni(NH_(3))_(6)]SO_(4)`
`(iv) K_(2)[PtCl_(6)]. " " (v) [V(H_(2)O)_(6)]SO_(4) " " (vi) [Mn(NH_(3))_(6)]SO_(4)`
`(vii)[Fe(H_(2)O)_(5)(NO)]SO_(4) " " (viii)K_(3)[CuCl_(4)]" " Na_(4)[Fe(CN)_(5)(NOS)]`

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The correct Answer is:
To determine the total number of paramagnetic complexes that are inner orbital complexes from the given list, we will analyze each complex step by step. ### Step 1: Analyze Each Complex 1. **Complex (i): [Cr(NH₃)₆]Cl₃** - Oxidation state of Cr: +3 - Electron configuration: Cr³⁺ (d³) - Hybridization: d²sp³ (inner orbital complex) - Paramagnetic: Yes (unpaired electrons) - **Conclusion**: Inner orbital and paramagnetic. 2. **Complex (ii): [Co(NH₃)₆](NO₃)₂** - Oxidation state of Co: +2 - Electron configuration: Co²⁺ (d⁷) - Hybridization: sp³d² (outer orbital complex) - Paramagnetic: Yes (unpaired electrons) - **Conclusion**: Not an inner orbital complex. 3. **Complex (iii): [Ni(NH₃)₆]SO₄** - Oxidation state of Ni: +2 - Electron configuration: Ni²⁺ (d⁸) - Hybridization: sp³d² (outer orbital complex) - Paramagnetic: Yes (unpaired electrons) - **Conclusion**: Not an inner orbital complex. 4. **Complex (iv): K₂[PtCl₆]** - Oxidation state of Pt: +4 - Electron configuration: Pt⁴⁺ (d⁶) - Hybridization: d²sp³ (inner orbital complex) - Paramagnetic: No (all electrons paired) - **Conclusion**: Not paramagnetic. 5. **Complex (v): [V(H₂O)₆]SO₄** - Oxidation state of V: +2 - Electron configuration: V²⁺ (d³) - Hybridization: d²sp³ (inner orbital complex) - Paramagnetic: Yes (unpaired electrons) - **Conclusion**: Inner orbital and paramagnetic. 6. **Complex (vi): [Mn(NH₃)₆]SO₄** - Oxidation state of Mn: +2 - Electron configuration: Mn²⁺ (d⁵) - Hybridization: sp³d² (outer orbital complex) - Paramagnetic: Yes (unpaired electrons) - **Conclusion**: Not an inner orbital complex. 7. **Complex (vii): [Fe(H₂O)₅(NO)]SO₄** - Oxidation state of Fe: +3 - Electron configuration: Fe³⁺ (d⁵) - Hybridization: sp³d² (outer orbital complex) - Paramagnetic: Yes (unpaired electrons) - **Conclusion**: Not an inner orbital complex. 8. **Complex (viii): K₃[CuCl₄]** - Oxidation state of Cu: +1 - Electron configuration: Cu¹⁺ (d¹⁰) - Hybridization: sp³ (outer orbital complex) - Paramagnetic: No (all electrons paired) - **Conclusion**: Not paramagnetic. 9. **Complex (ix): Na₄[Fe(CN)₅(NO)]** - Oxidation state of Fe: +2 - Electron configuration: Fe²⁺ (d⁶) - Hybridization: d²sp³ (inner orbital complex) - Paramagnetic: No (all electrons paired due to strong field ligands) - **Conclusion**: Not paramagnetic. ### Step 2: Count the Paramagnetic Inner Orbital Complexes From the analysis: - Complex (i): [Cr(NH₃)₆]Cl₃ - Inner orbital, paramagnetic. - Complex (v): [V(H₂O)₆]SO₄ - Inner orbital, paramagnetic. ### Final Answer The total number of paramagnetic complexes that are inner orbital complexes is **2**.
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[Co(NH_(3))_(5)NO_(2)]SO_(4) shows

Arrange the following compounds in order of increasing molar conductivity . (i) K[Co(NH_(3))_(2)(NO_(2))_(4)]" " (ii) [Cr(NH_(3))_(3)(NO_(2))_(3)] (iii) [Cr(NH_(3))_(5)(NO_(2))]_(3)[Co(NO_(2))_(6)]_(2)" " (iv) [Cr(NH_(3))_(6)]Cl_(3)

Using IUPAC norms, write the names of the following: (i) [CO(NH_(3))_(6)]Cl_(3) (ii) [PtCl(NH_(3))_(2)(NH_(2)CH_(3))]Cl (iii)[Ti (H_(2)O)_(6)]^(3+) (iv) [Co(NH_(3))_(4)Cl(NO_(2))]Cl (V) [Mn (H_(2)O)_(6)]^(2+) (vi) [NiCl_(4)]^(2-) (vii) [Ni (NH_(3))_(6)^(2)]Cl_(2) (vill) [Co (en)_(3)]^(3+) (ix) [Ni (CO)_(4)

In the give complexes (i). [Co(NH_(3))_(5)(H_(2)O)]^(3+) (ii). [Co(NH_(3))_(5)Cl]^(2+) (iii). [Co(NH_(3))_(6)]^(3+) The decreasing order of lamda absorbed is

[Cr(NH_(3))_(6)]^(3+)+6HCl to Cr^(3+)(aq)+6NH_(4)Cl

How many of the following will volatilize on heating leaving no solid residue ? (i) NaNO_(3) " " (ii) NH_(4)NO_(3) " " (iii)Ca(H_(2)PO_(2)) " " (iv) NH_(4)HCO_(3) (v) N_(2)H_(5)HSO_(3) " " (vi)AlCl_(3) " " (vii) [Cu(NH_(3))_(4)]SO_(4) " " (viii) FeSO_(4), 7H_(2)O

Write the IUPAC name of the following : (i) [Co(NH_(3))_(6)]Cl_(3) (ii) [NiCl_(4)]^(2-) (iii) K_(3)[Fe(CN)_(6)]

Which would exhibit ionisation isomerism (a) [Co(NH_(3))_(6)][(C_(2)O_(4))_(3)] (b) [Co(NH_(3))_(5)Br]^(2+)SO_(4)^(2-) (c ) K_(3)[Fe(CN)_(6)] (d) K_(3)[Fe(C_(2)O_(4))_(3)] .

Calculate the EAN of central atom in the following complexes (a) [Cr(CO)_(6)]" "(b) [Fe(CN)_(6)]^(4-)" " (c ) [Fe(CO)_(5)] " " (d) [Co(NH_(3))_(6)]^(3+) (e ) [Ni(CO)_(4) " " (f) [Cu(CN)_(4)]^(3-)" "(g)[Pd(NH_(3))_(6)]^(4+)" " (h) [PtCl_(6)]^(2-)

What type of isomerism exists in the following pairs of complexes ? (i) [Co(NH_(3))_(5)NO_(3)]SO_(4) and [Co(NH_(3))_(5) SO_(4) ] NO_(3) (ii) [Co(en)(H_(2)O)_(2) Cl_(2)] Cl and [Co(en) (H_(2)O) Cl_(3) ] H_(2)O