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For the [Cr(H(2)O)(6)]^(2+) ion, the mea...

For the `[Cr(H_(2)O)_(6)]^(2+)` ion, the mean pairing energy P is found to `23500cm^(-1)`. The magnitude of `Delta_(0)` is `13900cm^(-1)`. Calculate the C.F.S.E. `(cm^(-1))` for this complex ion corresponding to high spin state (x) and low spin state (y). Write your answer as `((y-x)/(100))`.

Text Solution

Verified by Experts

The correct Answer is:
96
For a `d^(4)`ion in a high spin state.
CFSE`=-0.6Delta_(0)=-0.6xx(13,900 cm^(-1))=-8340 cm^(-1)`
For a `d^(4)` ion in a low spin state, the net CFSE is, `=-1.6Delta_(0)+P=-1.6xx(13,900 cm^(-1))+23500 cm^(-1)= +1,260 cm^(-1)`
Since `Delta_(0)(=13,900 cm^(-1)) lt P(=23,500 cm^(-1))`, the high spin configuration would be more stable .
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