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A: In the reaction, 2NaOH+H(2)SO(4) to...

A: In the reaction,
`2NaOH+H_(2)SO_(4) to Na_(2)SO_(4) + 2H_(2)O`
equivalents of NaOH, `Na_(2)SO_(4)` and `H_(2)SO_(4)` are equal.
R: `"Number of equivalents" = "number of moles" xx "n-factor"`.

Text Solution

Verified by Experts

Valency factor of base = 1
Here, two molecule of NaOH replaced `2H^(+)` ion from the `H_(2) SO_(4)`. Therefore, each molecule of NaOH replaced only one `H^(+)` ion of acid, so v.f = 1.
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RESONANCE ENGLISH-EQUIVALENT CONCEPT & TITRATIONS-Part -IV
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