What volume of water is required (in mL) to prepare 1 L of 1 M solution of `H_(2)SO_(4)` (density = 1.5g/mL) by using 109% oleum and water only (Take density of pure water = 1g/mL).

Explanation

To solve the problem of how much water is required to prepare 1 L of a 1 M solution of \( H_2SO_4 \) using 109% oleum, we can follow these steps:

### Step 1: Determine the mass of \( H_2SO_4 \) needed
To prepare a 1 M solution of \( H_2SO_4 \), we need 1 mole of \( H_2SO_4 \) in 1 liter of solution. The molar mass of \( H_2SO_4 \) is approximately 98 g/mol.

\[ \text{Mass of } H_2SO_4 = 1 \, \text{mol} \times 98 \, \text{g/mol} = 98 \, \text{g} \]
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