22.7 ml of N/10 `Na_(2)CO_(3)` solution neutralizes 10.2 ml of a dilute `H_(2)SO_(4)` . Then the volume of water that must be added to 400 ml of same `H_(2)SO_(4)` to make it exactly N/10 is

Options

A. 490.2 mL
B. 890.2 mL
C. 90.2 mL
D. 290.2 mL

Answer

A

Explanation

meq of `Na_(2)CO_(3)` = meq of `H_(2)SO_(4)`
`(1)/(10)xx22.7=Nxx10.2`
Normality = 0.2225 N
`0.2225xx400=(1)/(10)xxV_(f)`
or `V_(f)=890.2` mL
`:. ` Volume of `H_(2)O` mixed = 890.2-400=490.2 mL