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The equivalent mass of MnSO4 is half of ...

The equivalent mass of `MnSO_4` is half of its molecular mass when it is converted to

A

`Mn_(2)O_(3)`

B

`MnO_(2)`

C

`MnO_(4)^(-)`

D

`MnO_(4)^(2-)`

Text Solution

Verified by Experts

The correct Answer is:
B
Eq. mass = `("Molecular weight")/("Change in oxidation no of Mn")=("Mol.wt.")/(4-2)=("Mol. Wt.")/(2)`
(O.N. of Mn in `MnSO_(4)=+2`,O.N. of Mn in `MnO_(2)=+4`).
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