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During the electrolysis of conc H(2)SO(...

During the electrolysis of conc `H_(2)SO_(4)`, it was found that `H_(2)S_(2)O_(8)` and `O_(2)` liberated in a molar ratio of `3:1`. How many moles of `H_(2)` were found of moles of `H_(2)S_(2)O_(8)` ?
`(` Express your answer as `:3xx mol e s of H_(2),` integer answer is between 0 and 5`0`

A

water

B

oxygen

C

both (1) & (2)

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B

`O_(3)` will oxidise `H_(2)O_(2)` into oxygen, hence radioacitve oxygen of `H_(2)O_(2)` will go only in oxygen, not in water.
Half reactions : `O_(3)+2H^(+)+2e^(-)rarrO_(2)H_(2)O` , `H_(2)O_(2)rarrO_(2)2H^(-)+2e^(-)`
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