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You are given a solution of an alkali. I...

You are given a solution of an alkali. In order to estimate its concentration in terms of normality , you need to know

A

the volume of the solution, the volume of the alkali present in it and its formula weight

B

the mass of the solution, the mass of the alkali present in it and its equivalent weight.

C

the volume of the solution, the solution, the mass of the alkali present in it and its equivalent weight.

D

the mass of the solution, the volume of the alkali present in it and its equivalent weight.

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The correct Answer is:
To estimate the concentration of an alkali solution in terms of normality, we need to follow these steps: ### Step-by-Step Solution: 1. **Understand Normality**: Normality (N) is defined as the number of gram equivalents of solute per liter of solution. The formula for normality can be expressed as: \[ N = \frac{\text{Number of gram equivalents}}{\text{Volume of solution in liters}} \] 2. **Identify the Components Needed**: To calculate normality, we need: - The volume of the solution (in liters). - The mass of the alkali (solute). - The equivalent mass (or equivalent weight) of the alkali. 3. **Calculate the Number of Gram Equivalents**: The number of gram equivalents can be calculated using the formula: \[ \text{Number of gram equivalents} = \frac{\text{Mass of alkali}}{\text{Equivalent mass of alkali}} \] 4. **Combine the Information**: Substitute the number of gram equivalents back into the normality formula: \[ N = \frac{\frac{\text{Mass of alkali}}{\text{Equivalent mass of alkali}}}{\text{Volume of solution in liters}} \] 5. **Conclusion**: To determine the normality of the alkali solution, we need: - The volume of the solution. - The mass of the alkali present in the solution. - The equivalent weight of the alkali. ### Final Answer: To estimate the concentration of the alkali solution in terms of normality, you need: - Volume of solution - Mass of alkali present in it - Equivalent weight of alkali
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RESONANCE ENGLISH-EQUIVALENT CONCEPT & TITRATIONS-APSP (Part-II)
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  2. The volume of water which must be added to 0.4 dm^(3) of 0.25 N oxali...

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  3. The quantity of electricity requried to reduce 0.05 mol of MnO(4)^(-)...

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  4. You are given a solution of an alkali. In order to estimate its concen...

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  5. Normality of a '30 volume H2O2' solution is:

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  6. Hydrazine N(2)H(4) acts as a reducing agent. To prepare 100 ml of 2 N...

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  7. For the reaction shown below, which statement is true ? 2Fe+3CdCl(2...

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  8. 5H(2)C(2)O(4)(aq)+2MnO(4)(aq)+6H^(+)(aq) to 2Mn^(2+)(aq)+10CO(2)(g)+8H...

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  9. What volume of water is requried to make 0.20 N solution from 1600 mL ...

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  10. Oxalic acid, H(2)C(2)O(4), reacts with paramagnet ion according to th...

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  11. A 500 g toothpaste sample has 0.4 g fluoride concentration. The fluori...

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  12. The number of moles of KMnO(4) that will be required to react with one...

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  13. Role of hydrogen peroxide iin the following reaction is respectively. ...

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  14. A bottle of H(3)PO(4) solution contains 70% acid. If the density of th...

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  15. The unbalanced equation for the reaction of P(4)S(3) with nitrate in a...

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  16. KMnO4 reacts with oxalic acid according to the equation 2MnO4 + 5C2 O4...

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  17. 1.250 g of metal carbonate (MCO(3)) was treated with 500 mL of 0.1 M H...

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  18. Battery acid (H(2)SO(4)) has density 1.285 g cm^(-3) , 10.0 cm^(3) of ...

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  19. A sample of water from a river was analyzed for the presence of metal ...

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  20. RH(2) ( ion exchange resin) can replace Ca^(2+)d in hard water as. R...

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