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100 milli moles of dichloroacetic acid ...

100 milli moles of dichloroacetic acid `(CHCl_(2)CO OH)` can neutralize how many moles of ammonia to form ammonium dichloroacetate :

A

0.0167

B

0.1

C

0.3

D

0.6

Text Solution

Verified by Experts

The correct Answer is:
B

`:. ` v.f. of dichloroacetic acid `= 2 ( 4 - 2) + 2(0- (-1))=6`
m.eq. of dichloroacetic acid = m.eq. of oxidising agent = 600
`:. ` m.moles of dichloroacetic acid `=(600)/(6)=100`
`CHCl_(2)CO OH+NH_(3)rarrCHCl_(2)CO ONH_(4)`
From reaction, m.moles of `NH_(3)` = m.moles of dichloroacetic acid = 100
`:.` Moles of `NH_(3)=(100)/(1000)=0.1`
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