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20mL of H(2)O(2) after acidification wit...

20mL of `H_(2)O_(2)` after acidification with dilute `H_(2)SO_(4)` required 30mL of N/2 `KMnO_(4)` for complete oxidation. Calculate the percentage of `H_(2)O_(2)` in the solution. Equivalent mass of `H_(2)O_(2)=17`.

A

2 g/L

B

4 g/L

C

8 g/L

D

6 g/L

Text Solution

Verified by Experts

The correct Answer is:
A
meq. Of `KMnO_(4)` = meq of `H_(2)O_(2)`
`30xx(1)/(12)=20xxN' rArr N' = (30)/(12xx20)=(1)/(8)N`
`:. ` strength `=N'xx` equivalent mass `=(1)/(8)xx17=2.12` g/L.
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