If the number of N-atoms in 1 molecule of Hyponitrous acid is x and the basicity of Boric acid is y, fing the sum (x+y).

Explanation

To solve the problem, we need to determine two values: the number of nitrogen (N) atoms in one molecule of hyponitrous acid and the basicity of boric acid. We will denote the number of N atoms as \( x \) and the basicity of boric acid as \( y \). Finally, we will find the sum \( x + y \).

### Step 1: Determine the number of N atoms in hyponitrous acid
Hyponitrous acid has the chemical formula \( H_2N_2O_2 \).

- **Count the N atoms**: In the formula \( H_2N_2O_2 \), there are 2 nitrogen (N) atoms.
- Therefore, we have:
\[ x = 2 \]

### Step 2: Determine the basicity of boric acid
Boric acid has the chemical formula \( H_3BO_3 \).

- **Understanding basicity**: Basicity refers to the number of hydrogen ions (H⁺) that an acid can donate. Boric acid can donate one H⁺ ion when it reacts with water, forming the tetrahydroxyborate ion \( B(OH)_4^- \).
- Therefore, the basicity \( y \) of boric acid is:
\[ y = 1 \]

### Step 3: Calculate the sum \( x + y \)
Now that we have both values:
- \( x = 2 \)
- \( y = 1 \)

We can find the sum:
\[ x + y = 2 + 1 = 3 \]

### Final Answer
The sum \( x + y \) is \( 3 \).

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