A solution of `Na_(2)S_(2)O_(3)` is standardized iodometrically against 0.167g of `KBrO_(3)`. The process requires 50mL of the `Na_(2)S_(2)O_(4)` solution. What is the normality of the `Na_(2)S_(3)O_(3)?`

Answer

3

Explanation

Necessary equations :
`KBrO_(3)+KIrarrI_(2)Br^(-)`
`I_(2)+Na_(2)S_(2)O_(3)rarrNa_(2)S_(4)O_(6)+`Nal
equivalent of `I_(2)` = equivalent of `KBrO_(3)=12xx10^(-2)`
equivalent of `Na_(2)S_(2)O_(3)=`equivalent of `KBrO_(3)=12xx10^(-2)`
equivalent of `Na_(2)S_(2)O_(3)`=equivalent of `I_(2)`
`Mxx1xx(40)/(1000)=12xx10^(-2)`
so molarity = 3M.