`XeF_2` on complete hydrolysis gives:

Options

A. Xe
B. `XeO_2`
C. `XeO_2F_2 `
D. `XeO_4`

Answer

To determine what `XeF2` (xenon difluoride) produces upon complete hydrolysis, we can follow these steps:

### Step 1: Understand the Hydrolysis Reaction
Hydrolysis is a chemical reaction involving the breaking of a bond in a molecule using water. In this case, we are looking at the hydrolysis of xenon difluoride.

### Step 2: Write the Hydrolysis Equation
When xenon difluoride reacts with water, the reaction can be represented as follows:

\[ \text{XeF}_2 + 2 \text{H}_2\text{O} \rightarrow \text{Xe} + 2 \text{HF} + \text{O}_2 \]

### Step 3: Identify the Products
From the equation, we can see that the products of the hydrolysis of xenon difluoride are:
- Xenon (Xe)
- Hydrogen fluoride (HF)
- Oxygen (O2)

### Step 4: Count the Molecules
In the reaction, for every molecule of `XeF2`, we produce:
- 1 molecule of Xenon (Xe)
- 2 molecules of Hydrogen fluoride (HF)
- 1 molecule of Oxygen (O2)

### Conclusion
Thus, upon complete hydrolysis of `XeF2`, we obtain:
- Xenon (Xe)
- Hydrogen fluoride (HF)
- Oxygen (O2)

### Final Answer
The correct answer is: **Xe + 2 HF + O2**

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