Excess fluorine reacts with ammonia to form :

Options

A. `NH_4F+HF`
B. `NH_5+HF`
C. `NF_3+HF`
D. `NH_4F+NF_5`

Answer

To solve the question regarding the reaction of excess fluorine with ammonia, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are ammonia (NH₃) and excess fluorine (F₂).

### Step 2: Understand the Reaction Conditions
The question specifies that there is an excess of fluorine. This means that there will be more fluorine available than what is needed to react with ammonia.

### Step 3: Write the Possible Reaction
When ammonia reacts with fluorine, the products formed are nitrogen trifluoride (NF₃) and hydrogen fluoride (HF). The reaction can be summarized as follows:

\[ \text{NH}_3 + 3 \text{F}_2 \rightarrow \text{NF}_3 + 3 \text{HF} \]

### Step 4: Identify the Products
From the reaction, we can see that the products formed are:
1. Nitrogen trifluoride (NF₃)
2. Hydrogen fluoride (HF)

### Step 5: Conclusion
Thus, when excess fluorine reacts with ammonia, the products formed are nitrogen trifluoride and hydrogen fluoride.

### Final Answer
The correct answer is:
**Nitrogen trifluoride (NF₃) and Hydrogen fluoride (HF)**.