Two gases X and Y bring about bleaching of flowers. X bleaches due to oxidation of dye while Y bleaches by reducing the colouring matter. X and Y are respectively

Options

A. (1) `SO_2, Cl_2`
B. (2) `Cl_2, SO_2`
C. `SO_2, O_2`
D. (4) None of these

Answer

To solve the question regarding the two gases X and Y that bleach flowers through different mechanisms, we can follow these steps:

### Step 1: Identify the Mechanism of Bleaching for Gas X
- The problem states that gas X bleaches due to the oxidation of the dye.
- A common gas known for its bleaching properties through oxidation is chlorine (Cl2).

### Step 2: Understand the Reaction of Gas X
- Chlorine gas (Cl2) reacts with water to form hydrochloric acid (HCl) and hypochlorous acid (HOCl).
- The hypochlorous acid can further dissociate, releasing oxygen (O) which acts as the bleaching agent through oxidation.

### Step 3: Identify the Mechanism of Bleaching for Gas Y
- The problem states that gas Y bleaches by reducing the coloring matter.
- A common gas known for its reducing properties and bleaching effect is sulfur dioxide (SO2).

### Step 4: Understand the Reaction of Gas Y
- Sulfur dioxide (SO2) can dissolve in water to form sulfurous acid (H2SO3) and can also release hydrogen atoms which act as reducing agents.
- This reduction process helps in bleaching by breaking down the coloring matter.

### Step 5: Conclusion
- Based on the above analysis, we can conclude that:
- Gas X is chlorine (Cl2), which bleaches by oxidation.
- Gas Y is sulfur dioxide (SO2), which bleaches by reduction.

### Final Answer
- Therefore, the gases X and Y are respectively: **Chlorine (Cl2)** and **Sulfur Dioxide (SO2)**.

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