What are the products formed in the reaction of xenon hexafluoride with silicon dioxide?

Options

A. (1) `XeSiO_4 + HF`
B. (2) `XeF_2+ SiF_4`
C. (3)`XeOF_4 + SiF_4 `
D. (4)`XeO_3 + SiF_2`

Explanation

To determine the products formed in the reaction of xenon hexafluoride (XeF6) with silicon dioxide (SiO2), we can follow these steps:

### Step 1: Write the Reactants
The reactants in this reaction are:
- Xenon hexafluoride (XeF6)
- Silicon dioxide (SiO2)

### Step 2: Identify the Reaction
Xenon hexafluoride can react with silicon dioxide to form xenon trioxide (XeO3) and silicon tetrafluoride (SiF4). The reaction can be summarized as follows:

\[ \text{XeF}_6 + \text{SiO}_2 \rightarrow \text{XeO}_3 + \text{SiF}_4 \]

### Step 3: Balance the Reaction
To ensure the reaction is balanced, we need to check the number of atoms of each element on both sides of the equation.

1. **Xenon (Xe)**: 1 on both sides.
2. **Fluorine (F)**: 6 on the left (from XeF6) and 4 on the right (from SiF4).
3. **Silicon (Si)**: 1 on both sides.
4. **Oxygen (O)**: 2 on the left (from SiO2) and 3 on the right (from XeO3).

To balance the equation, we can multiply the compounds appropriately:

\[ 2 \text{XeF}_6 + \text{SiO}_2 \rightarrow 2 \text{XeO}_3 + 2 \text{SiF}_4 \]

Now, we have:
- Xenon: 2 on both sides
- Fluorine: 12 on the left (from 2 XeF6) and 8 on the right (from 2 SiF4)
- Silicon: 1 on both sides
- Oxygen: 2 on the left and 6 on the right

### Step 4: Final Balanced Equation
The balanced equation is:

\[ 2 \text{XeF}_6 + 3 \text{SiO}_2 \rightarrow 2 \text{XeO}_3 + 6 \text{SiF}_4 \]

### Step 5: Identify the Products
From the balanced equation, the products formed are:
- Xenon trioxide (XeO3)
- Silicon tetrafluoride (SiF4)

### Conclusion
The products formed in the reaction of xenon hexafluoride with silicon dioxide are xenon trioxide (XeO3) and silicon tetrafluoride (SiF4).