`ClO_2 + Na_2O_2 rarr A+B`
(A) and (B) are:

Options

A. (A)=`NaCl , (B) =O_2`
B. `(A)=NaClO_2 , (B)=O_2`
C. `(A)=Na_2O, (B) =Cl_2O`
D. `(A)=Cl_2 , (B)=Na_2 O`

Explanation

To solve the reaction \( \text{ClO}_2 + \text{Na}_2\text{O}_2 \rightarrow A + B \), we need to identify the products formed when chlorine dioxide reacts with sodium peroxide.

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Chlorine dioxide (\( \text{ClO}_2 \))
- Sodium peroxide (\( \text{Na}_2\text{O}_2 \))

### Step 2: Understand the Reaction
When \( \text{ClO}_2 \) reacts with \( \text{Na}_2\text{O}_2 \), it undergoes a redox reaction. Sodium peroxide can act as an oxidizing agent, and chlorine dioxide can be reduced.

### Step 3: Determine the Products
The products of this reaction are:
- Sodium chlorate (\( \text{NaClO}_2 \))
- Oxygen gas (\( \text{O}_2 \))

Thus, we can write the reaction as:
\[ \text{ClO}_2 + \text{Na}_2\text{O}_2 \rightarrow \text{NaClO}_2 + \text{O}_2 \]

### Step 4: Assign the Products
From the above reaction:
- Product A (\( A \)) is sodium chlorate (\( \text{NaClO}_2 \))
- Product B (\( B \)) is oxygen gas (\( \text{O}_2 \))

### Conclusion
The final answer is:
- \( A = \text{NaClO}_2 \)
- \( B = \text{O}_2 \)