Which of the following on treatment with `XeF_6`gives Xe ?

Options

A. `H_2`
B. `HCl`
C. `OH^-` (conc)
D. All of these

Explanation

To solve the question of which of the following substances, when treated with `XeF_6`, gives Xenon (Xe), we will analyze the possible reactions step by step.

### Step 1: Understand the Reaction with `XeF_6`
`XeF_6` is a fluorinating agent and can react with various substances to release Xenon. We need to identify the reactants that can lead to the formation of Xenon when treated with `XeF_6`.

### Step 2: Reaction with Hydrogen (H2)
When `XeF_6` reacts with hydrogen, the reaction can be represented as:
\[ \text{XeF}_6 + \text{H}_2 \rightarrow \text{Xe} + 6 \text{HF} \]
This shows that `XeF_6` reacts with `H2` to produce Xenon and hydrofluoric acid (HF).

### Step 3: Reaction with Hydrochloric Acid (HCl)
Next, we consider the reaction with hydrochloric acid:
\[ \text{XeF}_6 + 6 \text{HCl} \rightarrow \text{Xe} + 6 \text{HF} + 3 \text{Cl}_2 \]
This indicates that `XeF_6` can also react with `HCl` to yield Xenon, HF, and chlorine gas.

### Step 4: Reaction with Hydroxide Ion (OH-)
Now, we analyze the reaction with hydroxide ions:
\[ \text{XeF}_6 + 6 \text{OH}^- \rightarrow \text{Xe(OH)}_6 + 6 \text{HF} + 6 \text{Cl} \]
This reaction shows that `XeF_6` reacts with hydroxide ions to produce a hydroxylated form of Xenon and HF.

### Step 5: Conclusion
From the reactions analyzed, we can conclude that `XeF_6` reacts with hydrogen, hydrochloric acid, and hydroxide ions to produce Xenon. Therefore, all of the given options (A, B, C, and D) lead to the formation of Xenon.

### Final Answer
The correct option is D, as all the mentioned reactants can produce Xenon when treated with `XeF_6`.

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