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How many n-octene can show geometrical i...

How many n-octene can show geometrical isomerism?

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To determine how many n-octenes can show geometrical isomerism, we need to analyze the structures of n-octene and identify the presence of double bonds and substituents around those double bonds. ### Step-by-Step Solution: 1. **Understanding Geometrical Isomerism**: - Geometrical isomerism occurs in alkenes (compounds with a carbon-carbon double bond) when there are different groups attached to the carbon atoms involved in the double bond. - For geometrical isomerism to occur, the two groups attached to each carbon of the double bond must be different. This means that if we have a structure like C=C with groups R1, R2 on one carbon and R3, R4 on the other, R1 must not equal R2 and R3 must not equal R4. 2. **Identifying the Structure of n-Octene**: - n-Octene has the formula C8H16 and can be represented as CH3(CH2)5CH=CH2. - It can exist in several structural forms (isomers) depending on the position of the double bond. 3. **Analyzing Different Isomers**: - The possible positions for the double bond in n-octene are between the following carbon atoms: - Between C1 and C2 - Between C2 and C3 - Between C3 and C4 - Between C4 and C5 - Between C5 and C6 - Between C6 and C7 - We will analyze each of these positions to see if they can exhibit geometrical isomerism. 4. **Position of the Double Bond**: - **1-Octene (C1=C2)**: This cannot show geometrical isomerism because both groups on C1 are hydrogen. - **2-Octene (C2=C3)**: This can show geometrical isomerism since C2 has CH3 and H, and C3 has H and CH2(CH2)3CH3. This gives rise to cis (same side) and trans (opposite side) isomers. - **3-Octene (C3=C4)**: Similar to 2-octene, this can also show geometrical isomerism with different groups on C3 and C4. - **4-Octene (C4=C5)**: This can show geometrical isomerism as well. - **5-Octene (C5=C6)**: This can also show geometrical isomerism. - **6-Octene (C6=C7)**: This cannot show geometrical isomerism because both groups on C6 are hydrogen. 5. **Counting the Isomers**: - From the analysis: - 1-Octene: 0 isomers - 2-Octene: 2 isomers (cis and trans) - 3-Octene: 2 isomers (cis and trans) - 4-Octene: 2 isomers (cis and trans) - 5-Octene: 2 isomers (cis and trans) - 6-Octene: 0 isomers - Total geometrical isomers = 0 + 2 + 2 + 2 + 2 + 0 = 8. ### Final Answer: Thus, the total number of n-octenes that can show geometrical isomerism is **8**.
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