`CH_3OC_2H_5` + `PCl_5``to`

Answer

To solve the question regarding the reaction of ethyl methyl ether (CH₃OC₂H₅) with phosphorus pentachloride (PCl₅), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are ethyl methyl ether (CH₃OC₂H₅) and phosphorus pentachloride (PCl₅).

2. **Understand the Reaction Mechanism**:
Phosphorus pentachloride (PCl₅) is a strong chlorinating agent. It reacts with ethers to cleave the ether bond, leading to the formation of alkyl chlorides and phosphorus oxychloride (POCl₃).

3. **Write the Reaction**:
The reaction can be written as:
\[ \text{CH}_3\text{OC}_2\text{H}_5 + \text{PCl}_5 \rightarrow \text{CH}_3\text{Cl} + \text{C}_2\text{H}_5\text{Cl} + \text{POCl}_3 \]

4. **Identify the Products**:
- The products formed from this reaction are:
- Methyl chloride (CH₃Cl)
- Ethyl chloride (C₂H₅Cl)
- Phosphorus oxychloride (POCl₃)

5. **Summarize the Reaction**:
Thus, the overall reaction can be summarized as:
\[ \text{CH}_3\text{OC}_2\text{H}_5 + \text{PCl}_5 \rightarrow \text{CH}_3\text{Cl} + \text{C}_2\text{H}_5\text{Cl} + \text{POCl}_3 \]

### Final Answer:
The products formed from the reaction of CH₃OC₂H₅ with PCl₅ are CH₃Cl, C₂H₅Cl, and POCl₃.

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