Total number of stereoisomers of compound is:
`CH_(3)-underset(overset(|)(OH))(C)H-underset(overset(|)(Br))(C)H-CH_(3)`

Options

A. 2
B. 4
C. 6
D. 8

Answer

To determine the total number of stereoisomers for the compound `CH3-CH(OH)-CH(Br)-CH3`, we will follow these steps:

### Step 1: Identify the Structure
The given compound can be represented as follows:
- Carbon 1 (C1): CH3
- Carbon 2 (C2): CH(OH)
- Carbon 3 (C3): CH(Br)
- Carbon 4 (C4): CH3

### Step 2: Identify Stereogenic Centers
A stereogenic center (or chiral center) is a carbon atom that has four different substituents.

- **C2**: The substituents are:
- OH (hydroxyl group)
- CH3 (methyl group)
- H (hydrogen)
- CH(Br) (the carbon bonded to bromine)

Since all four substituents are different, C2 is a stereogenic center.

- **C3**: The substituents are:
- Br (bromine)
- CH3 (methyl group)
- H (hydrogen)
- CH(OH) (the carbon bonded to hydroxyl group)

Again, all four substituents are different, so C3 is also a stereogenic center.

### Step 3: Count the Stereogenic Centers
We have identified 2 stereogenic centers (C2 and C3).

### Step 4: Calculate the Number of Stereoisomers
The number of stereoisomers for a compound with n stereogenic centers can be calculated using the formula:
\[ \text{Number of stereoisomers} = 2^n \]
where n is the number of stereogenic centers.

Here, \( n = 2 \):
\[ \text{Number of stereoisomers} = 2^2 = 4 \]

### Conclusion
Thus, the total number of stereoisomers for the compound is **4**.

### Final Answer
The correct option is **B (4)**.

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