Which of the following molecules possess a plane of symmetry ?

Options

A.
B.
C.
D. More than one of these

Answer

To determine which of the given molecules possesses a plane of symmetry, we need to analyze the molecular structures based on the symmetry of their substituents around the central atom. A plane of symmetry is an imaginary plane that divides a molecule into two mirror-image halves.

### Step-by-Step Solution:

1. **Identify the Molecules**:
- We have three compounds to analyze. Let's denote them as Compound A, Compound B, and Compound C.

2. **Analyze Compound A**:
- The substituents around the central carbon atom are different: R1, K, CF, R, and X.
- Since all substituents are different, there is no way to divide the molecule into two identical halves.
- **Conclusion**: Compound A does not possess a plane of symmetry.

3. **Analyze Compound B**:
- The substituents around the central carbon atom are: Carbon, Fluorine, Fluorine, and Bromine.
- Here, we have two identical substituents (Fluorine).
- This allows for a plane of symmetry to be drawn between the two Fluorine atoms, dividing the molecule into two symmetrical halves.
- **Conclusion**: Compound B possesses a plane of symmetry.

4. **Analyze Compound C**:
- The substituents around the central carbon atom are also different, similar to Compound A.
- Since all substituents are different, there is no plane of symmetry.
- **Conclusion**: Compound C does not possess a plane of symmetry.

5. **Final Answer**:
- The molecule that possesses a plane of symmetry is **Compound B**.