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Which of the following compunds is capab...

Which of the following compunds is capable of showing geometrical, optical and conformational isomerism.

A

B

`H_(2)C=CH-underset(overset(|)(OH))(C)H-CH_(3)`

C

`CH_(3)-CH=CH-CH_(2)-CH_(2)-OH`

D

`H_(2)C=CH-CH_(2)-OH`

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AI Generated Solution

The correct Answer is:
To determine which of the given compounds is capable of showing geometrical, optical, and conformational isomerism, we will analyze each type of isomerism step by step. ### Step 1: Analyze Geometrical Isomerism Geometrical isomerism occurs due to the restricted rotation around a double bond or a ring structure, leading to different spatial arrangements of substituents. 1. **Compound 1**: This compound has an allene structure with consecutive double bonds, making it planar. It can show cis-trans isomerism because the substituents can be arranged differently around the double bond. - **Conclusion**: Shows geometrical isomerism. 2. **Compound 2**: This compound has two identical groups (H) on one side of the double bond, which means it cannot exhibit geometrical isomerism. - **Conclusion**: Does not show geometrical isomerism. 3. **Compound 3**: This compound has different groups on either side of the double bond (H and CH3 on one side, H and CH2CH2OH on the other). Thus, it can show E/Z isomerism. - **Conclusion**: Shows geometrical isomerism. 4. **Compound 4**: Similar to Compound 2, it has two identical groups on one side, so it cannot exhibit geometrical isomerism. - **Conclusion**: Does not show geometrical isomerism. ### Step 2: Analyze Optical Isomerism Optical isomerism occurs when a compound has chiral centers, leading to non-superimposable mirror images. 1. **Compound 1**: Contains a chiral center (carbon attached to different substituents), hence it can show optical isomerism. - **Conclusion**: Shows optical isomerism. 2. **Compound 2**: Contains a chiral center as well, thus it can show optical isomerism. - **Conclusion**: Shows optical isomerism. 3. **Compound 3**: This compound does not have any chiral centers, so it cannot show optical isomerism. - **Conclusion**: Does not show optical isomerism. 4. **Compound 4**: Similar to Compound 3, it lacks chiral centers, hence does not show optical isomerism. - **Conclusion**: Does not show optical isomerism. ### Step 3: Analyze Conformational Isomerism Conformational isomerism arises from the rotation around single bonds, leading to different spatial arrangements (conformers). 1. **Compound 1**: Being planar, it does not have conformational isomerism. - **Conclusion**: Does not show conformational isomerism. 2. **Compound 2**: This compound can exhibit conformational isomerism due to the presence of different substituents that can adopt staggered or eclipsed conformations. - **Conclusion**: Shows conformational isomerism. 3. **Compound 3**: This compound also has the ability to show conformational isomerism due to the presence of single bonds allowing rotation. - **Conclusion**: Shows conformational isomerism. 4. **Compound 4**: This compound does not have any conformational isomerism due to its structure. - **Conclusion**: Does not show conformational isomerism. ### Final Conclusion Based on the analysis: - **Compound 1**: Shows geometrical and optical isomerism but not conformational. - **Compound 2**: Shows optical and conformational isomerism but not geometrical. - **Compound 3**: Shows geometrical and conformational isomerism but not optical. - **Compound 4**: Does not show any of the isomerisms. Thus, **Compound 2** is the only compound capable of showing geometrical, optical, and conformational isomerism.
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RESONANCE ENGLISH-STEREOISOMERISM-EXERCISE (ADDITIONAL PROBLEMS FOR SELF PRACTICE (APSP)) PART 1
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  6. Which pair is identical ?

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  8. The correct IUPAC name of D-Glucose is :

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  9. Which of the following species will be optically active ?

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  10. Which of the following compounds exhibits stereoisomerism?

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  11. The isomeric alcohol which has a chiral carbon atom is :1

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  12. Which of the following are intensive properties?

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  14. Which of the following will not show geometrical isomerism?

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  18. The two compounds (I) and (II) are related as :

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