Ammonia reacts with red -hot cupric oxide to produce

Options

A. `Cu_(2)O, N_(2), H_(2)`
B. `Cu, H_(2)O, N_(2)`
C. `Cu(OH)_(2), N_(2)`
D. `[Cu(NH_(3))_(4)] (OH)_(2)`

Answer

To solve the question regarding the reaction of ammonia with red-hot cupric oxide, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this reaction are ammonia (NH₃) and cupric oxide (CuO).

2. **Understand the Reaction Conditions**: The cupric oxide is red-hot, which indicates that it is in a state that can facilitate oxidation reactions.

3. **Write the Balanced Chemical Equation**: When ammonia is passed over red-hot cupric oxide, it undergoes oxidation. The balanced chemical equation for this reaction is:
\[ 3 \text{CuO} + 2 \text{NH}_3 \rightarrow 3 \text{Cu} + 3 \text{H}_2\text{O} + \text{N}_2 \]
Here, ammonia (NH₃) is oxidized to nitrogen gas (N₂), and cupric oxide (CuO) is reduced to copper (Cu).

4. **Identify the Products**: From the balanced equation, we can see that the products of the reaction are:
- Copper (Cu)
- Water (H₂O)
- Nitrogen gas (N₂)

5. **Select the Correct Option**: Based on the products formed, the correct answer to the question is:
- Copper (Cu)
- Water (H₂O)
- Nitrogen gas (N₂)

### Conclusion:
Thus, the reaction of ammonia with red-hot cupric oxide produces copper, water, and nitrogen gas.