How many of the following compound on hydrolysis form HCl?
(i)`NaCl` (ii) `PCl_(5)` (iii) `CH_(3)Cl` (iv) `NH_(4)Cl` (v) `BaCl_(2)`

Answer

To determine how many of the given compounds form HCl upon hydrolysis, we will analyze each compound one by one.

### Step 1: Analyze NaCl
- **Hydrolysis Reaction**: NaCl + H2O → NaOH + HCl
- **Conclusion**: NaCl hydrolyzes to form HCl.

### Step 2: Analyze PCl5
- **Hydrolysis Reaction**: PCl5 + H2O → H3PO4 + 5HCl
- **Conclusion**: PCl5 hydrolyzes to form HCl.

### Step 3: Analyze CH3Cl
- **Hydrolysis Reaction**: CH3Cl + H2O → CH3OH + HCl
- **Conclusion**: CH3Cl hydrolyzes to form HCl.

### Step 4: Analyze NH4Cl
- **Hydrolysis Reaction**: NH4Cl + H2O → NH4OH + HCl
- **Conclusion**: NH4Cl hydrolyzes to form HCl.

### Step 5: Analyze BaCl2
- **Hydrolysis Reaction**: BaCl2 + H2O → Ba(OH)2 + 2HCl
- **Conclusion**: BaCl2 hydrolyzes to form HCl.

### Final Conclusion
All five compounds (NaCl, PCl5, CH3Cl, NH4Cl, and BaCl2) produce HCl upon hydrolysis.

**Total Count**: 5 compounds form HCl upon hydrolysis.

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