`PCl_(5)+H_(2)O rarr X+HCl`
If X is oxyacid of phosphorus, then correct statment is

Options

A. X is `H_(3)PO_(4)`
B. X is `H_(3)PO_(2)`
C. X is `H_(3)PO_(3)`
D. X is `HPO_(3)`

Answer

To solve the question, we need to analyze the reaction given and identify the product (X) formed when phosphorus pentachloride (PCl5) reacts with water (H2O).

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in the reaction are phosphorus pentachloride (PCl5) and water (H2O).

2. **Write the Reaction**: The reaction can be written as:
\[ \text{PCl}_5 + \text{H}_2\text{O} \rightarrow X + \text{HCl} \]

3. **Determine the Product (X)**: When PCl5 reacts with water, it hydrolyzes to form an oxyacid of phosphorus and hydrochloric acid (HCl). The hydrolysis of PCl5 typically leads to the formation of phosphoric acid (H3PO4).

4. **Identify the Oxyacid**: The product X is an oxyacid of phosphorus. The possible oxyacids of phosphorus include:
- H3PO4 (phosphoric acid)
- H3PO3 (phosphorous acid)
- H3PO2 (hypophosphorous acid)
- HPO3 (metaphosphoric acid)

Among these, H3PO4 is the most common product formed from the hydrolysis of PCl5.

5. **Conclusion**: Therefore, the correct statement regarding the product X is:
\[ X = \text{H}_3\text{PO}_4 \]

### Final Answer:
The correct statement is: **X is H3PO4.**

---