The nitrogen containing compound produced in the reaction of `NH_(3)` with sodium hypochlorite is

Options

A. `NCl_(3)`
B. `NH_(4)Cl`
C. `N_(2)O`
D. `N_(2)H_(4)`

Answer

To solve the question regarding the nitrogen-containing compound produced when ammonia reacts with sodium hypochlorite, we can follow these steps:

### Step 1: Write the Reactants
Identify the reactants involved in the reaction:
- Ammonia (NH₃)
- Sodium hypochlorite (NaOCl)

### Step 2: Understand the Reaction
When ammonia reacts with sodium hypochlorite, a chemical reaction occurs that leads to the formation of various products.

### Step 3: Write the Balanced Chemical Equation
The balanced chemical equation for the reaction can be written as follows:
\[ 2 \text{NH}_3 + \text{NaOCl} \rightarrow \text{N}_2\text{H}_4 + \text{NaCl} + \text{H}_2\text{O} \]
Here, the products formed are:
- Hydrazine (N₂H₄)
- Sodium chloride (NaCl)
- Water (H₂O)

### Step 4: Identify the Nitrogen-Containing Compound
From the balanced equation, we can see that the nitrogen-containing compound produced is hydrazine (N₂H₄).

### Step 5: Conclusion
Thus, the nitrogen-containing compound produced in the reaction of ammonia with sodium hypochlorite is hydrazine (N₂H₄).

### Final Answer:
The nitrogen-containing compound produced is **N₂H₄ (Hydrazine)**.

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