When `SOCl_(2)` reacts with `H_(2)O` products formed is/are:

Options

A. `HCl`
B. `H_(2)SO_(4)`
C. `S`
D. `SO_(2)`

Answer

To determine the products formed when thionyl chloride (SOCl₂) reacts with water (H₂O), we can follow these steps:

### Step 1: Write the reaction equation
When thionyl chloride reacts with water, the reaction can be represented as:
\[ \text{SOCl}_2 + \text{H}_2\text{O} \rightarrow \text{HCl} + \text{H}_2\text{SO}_4 + \text{S} \]

### Step 2: Identify the products
From the reaction, we can identify the products formed:
- Hydrogen chloride (HCl)
- Sulfuric acid (H₂SO₄)
- Sulfur (S)

### Step 3: Balance the reaction
To ensure the reaction is balanced, we can check the number of atoms of each element on both sides:
- **Sulfur (S)**: 1 on the left (in SOCl₂) and 1 on the right (in H₂SO₄ and S)
- **Chlorine (Cl)**: 2 on the left (in SOCl₂) and 2 on the right (in HCl)
- **Hydrogen (H)**: 2 on the left (in H₂O) and 2 on the right (in HCl and H₂SO₄)
- **Oxygen (O)**: 1 on the left (in H₂O) and 4 on the right (in H₂SO₄)

Thus, the balanced equation is:
\[ \text{SOCl}_2 + 2 \text{H}_2\text{O} \rightarrow 2 \text{HCl} + \text{H}_2\text{SO}_4 + \text{S} \]

### Conclusion
The products formed when SOCl₂ reacts with H₂O are:
- Hydrogen chloride (HCl)
- Sulfuric acid (H₂SO₄)
- Sulfur (S)

### Final Answer
The correct products formed are HCl, H₂SO₄, and S.

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