`PCl_(5)` on treatment with `SO_(2)` yields

Options

A. `POCl_(3)`
B. `SO_(2)Cl_(2)`
C. `SO_(3)`
D. `SOCl_(2)`

Answer

To solve the question regarding the reaction of phosphorus pentachloride (PCl₅) with sulfur dioxide (SO₂), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are phosphorus pentachloride (PCl₅) and sulfur dioxide (SO₂).

### Step 2: Understand the Reaction
When PCl₅ reacts with SO₂, it undergoes a chemical reaction that leads to the formation of phosphoryl chloride (POCl₃) and thionyl chloride (SOCl₂).

### Step 3: Write the Balanced Chemical Equation
The balanced chemical equation for the reaction can be represented as:
\[ PCl_5 + SO_2 \rightarrow POCl_3 + SOCl_2 \]

### Step 4: Analyze the Products
From the balanced equation, we can see that the products formed are:
1. Phosphoryl chloride (POCl₃)
2. Thionyl chloride (SOCl₂)

### Conclusion
Thus, when PCl₅ is treated with SO₂, it yields both POCl₃ and SOCl₂.

### Final Answer
The correct products formed when PCl₅ is treated with SO₂ are:
- Phosphoryl Chloride (POCl₃)
- Thionyl Chloride (SOCl₂)