`PCl_(5)` on treatment with `H_(2)SO_(4)` yields

Options

A. `POCl_(3)`
B. `SO_(2)`
C. `SO_(2)Cl_(2)`
D. `SOCl_(2)`

Answer

To solve the question regarding the reaction of PCl₅ with H₂SO₄, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are phosphorus pentachloride (PCl₅) and sulfuric acid (H₂SO₄).

### Step 2: Understand the Reaction
When PCl₅ reacts with H₂SO₄, it undergoes a hydrolysis reaction. This means that the phosphorus pentachloride will react with sulfuric acid to form different products.

### Step 3: Write the Balanced Chemical Equation
The reaction can be represented as follows:
\[ \text{PCl}_5 + \text{H}_2\text{SO}_4 \rightarrow \text{POCl}_3 + \text{SO}_2\text{Cl}_2 + \text{HCl} \]

### Step 4: Identify the Products
From the balanced equation, we can see that the products formed are:
1. Phosphoryl chloride (POCl₃)
2. Sulfuryl chloride (SO₂Cl₂)
3. Hydrochloric acid (HCl)

### Step 5: Conclusion
Thus, the treatment of PCl₅ with H₂SO₄ yields phosphoryl chloride (POCl₃) and sulfuryl chloride (SO₂Cl₂), along with hydrochloric acid (HCl).

### Final Answer
The correct products formed when PCl₅ reacts with H₂SO₄ are POCl₃ and SO₂Cl₂.

---